The given reaction is endothermic so, ΔH = +ve. For a reaction to be spontaneous ΔG must be negative.
ΔG = ΔH - TΔS = -ve (to be spontaneous)
Now, if ΔS = +ve then reaction will be spontaneous at high temperature (i.e., at boiling point of water) while it will be non-spontaneous at law temperature (i.e., at freezing point of water).
The given reaction is endothermic so, ΔH = +ve. For a reaction to be spontaneous ΔG must be negative.
ΔG = ΔH - TΔS = -ve (to be spontaneous)
Now, if ΔS = +ve then reaction will be spontaneous at high temperature (i.e., at boiling point of water) while it will be non-spontaneous at law temperature (i.e., at freezing point of water).