17. Let us consider a reversible reaction at temperature, T. In this reaction, both ΔH and ΔS were observed to have positive values. If the equilibrium temperature is T_e, then the reaction becomes spontaneous at
ΔG is negative for spontaneous reaction, and at equilibrium ΔG = 0.
ΔG = ΔH - TΔS
It is given that ΔH and ΔS both are positive, So to make ΔG negative, T must be higher than T_e
ΔG is negative for spontaneous reaction, and at equilibrium ΔG = 0.
ΔG = ΔH - TΔS
It is given that ΔH and ΔS both are positive, So to make ΔG negative, T must be higher than T_e
ΔG is negative for spontaneous reaction, and at equilibrium ΔG = 0.
ΔG = ΔH - TΔS
It is given that ΔH and ΔS both are positive, So to make ΔG negative, T must be higher than T_e