Directions (1 -2): Answer these questions based on the information given below.
There are five members A, B, C, D and E in a family. Ratio of ages of A and B five years ago was 3 : 4. Sum of ages of D and E five years hence will be 90. If C were born four years later than his actual date of birth, present Age of C would be half to that of present age E.
- What is the age of D four years ago, if the current age of C is 27 years?
(A - 5) : (B - 5) = 3 : 4 ----------(i)
D + E + 10 = 90 -----------------(ii)
C - 4 = 1/2 E ---------------(iii)
Current age of C = 27 years
According to equation (iii),
27 - 4 = 1/2 E
E = 46 years
According to equation (iii),
D + 46 + 10 = 90
D = 34 years
∴ Age of D four years ago was 30 years
(A - 5) : (B - 5) = 3 : 4 ----------(i)
D + E + 10 = 90 -----------------(ii)
C - 4 = 1/2 E ---------------(iii)
Current age of C = 27 years
According to equation (iii),
27 - 4 = 1/2 E
E = 46 years
According to equation (iii),
D + 46 + 10 = 90
D = 34 years
∴ Age of D four years ago was 30 years
(A - 5) : (B - 5) = 3 : 4 ----------(i)
D + E + 10 = 90 -----------------(ii)
C - 4 = 1/2 E ---------------(iii)
Current age of C = 27 years
According to equation (iii),
27 - 4 = 1/2 E
E = 46 years
According to equation (iii),
D + 46 + 10 = 90
D = 34 years
∴ Age of D four years ago was 30 years